Legend: Legacy of the Dragons Forum

Stick to the quests that are English only. And only start new quest when they have News Post on our portal. Anything else will be considered as Bug abuse and is punishable.

Quoted from "Yvil;38666"

Stick to the quests that are English only. And only start new quest when they have News Post on our portal. Anything else will be considered as Bug abuse and is punishable.

Please could you clarify your response. We were not trying exploit game bug, just merely trying to be first to upgrade our pets to purple. I know screen was in Russian, but we were able to read/translate, and it is fairly common for new updates to sometimes have a few issues and appear untranslated to start with, so despite this we were able to select what we wanted.

We paid 150g in good faith for upgraded pet, we were not trying to get it for free, but pay what game price is set at.

Purple pet is included / offered on Mentor site, so guessed it was now available. http://sites.google.com/site/info4wod/pets-and-mounts/pets

What is the situation, will we be getting purple pet or our 150g gold returned, please confirm. I cannot see how we can be punished as exploting bug when all we try is to better our character by paying correct price?

This is the English server of War of Dragons. Therefore any other language than English in parts of the game is an issue that has to be reported to the administration immediately. Using any feature in a different language is considered bug use, which is punishable. (Using a feature in a different language and then complaining that it did not work is audacious and fraudulent, if you ask me.)

For this reason we will handle the situation as follows: Any player who tried to use this quest has a choice. Either they can go to jail and get their money returned, or they can continue playing "as is" without a jailterm and without the money and wait on what they paid for to be added to the server later.

Anyone who choses jail and 150g, please contact support@warofdragons.com to arrange for a cell.